Quiz Chapter 05.02: Direct Method of Interpolation

MULTIPLE CHOICE TEST

(All Tests)

DIRECT INTERPOLATION

(More on Direct Interpolation)

INTERPOLATION

(More on Interpolation)


Pick the most appropriate answer


1. Given n+1 data pairs, a unique polynomial of degree _____ passes through the n+1 data points.

 
 
 
 

2. The following data of the velocity of a body is given as a function of time

Time (s) 0 15 18 22 24
Velocity (m/s) 22 24 37 25 123

The velocity in m/s at 16 s using linear polynomial interpolation is most nearly

 
 
 
 

3. The following data of the velocity of a body is given as a function of time

Time (s) 0 15 18 22 24
Velocity (m/s) 22 24 37 25 123

The velocity in m/s at 16 s using quadratic polynomial interpolation is most nearly

 
 
 
 

4. The following data of the velocity of a body is given as a function of time

Time (s) 0 15 18 22 24
Velocity (m/s) 22 24 37 25 123

Using quadratic interpolation, the interpolant

v (t) = 8.667t^{2} - 349.67t + 3523, \, 18 \leq t \leq 24

approximates the velocity of the body between 18 and 24 seconds. From this information, one of the times at which the velicty of the body is 35 m/s during the above time interval of t=18 s to 24 s is

 
 
 
 

5. The following data of the velocity of a body is given as a function of time

Time (s) 0 15 18 22 24
Velocity (m/s) 22 24 37 25 123

One of the interpolant approximations from the above data is given as

v(t) = 8.667t^{2} - 349.67t + 3523, \, 18 \leq t \leq 24

Using the above interpolant, the distance in meters covered by the body between t=19 s and t=22 s is most nearly

 
 
 
 

6. The following data of the velocity of a body is given as a function of time

Time (s) 0 15 18 22 24
Velocity (m/s) 22 24 37 25 123

If you were going to use quadratic interpolation to find the value of the velocity at t=14.9 seconds, the three data points of time that you would choose for interpolation are