HOW DO I DO THAT IN MATLAB SERIES?
In this series, I am answering questions that students have asked me about MATLAB.
Contents
TOPIC
How to solve nonlinear equations in MATLAB
SUMMARY
Language : Matlab 2008a; Authors : Sri Harsha Garapati, Daniel Miller, Autar Kaw; Mfile available at Last Revised : January 17, 2012; Abstract: This program shows how to solve a nonlinear equations.
clc
clear all
INTRODUCTION
disp('ABSTRACT') disp(' This program shows you an how to solve nonlinear equations') disp(' ') disp('AUTHOR') disp(' Sri Harsha Garapati, Daniel Miller and') disp('Autar K Kaw of http://autarkaw.wordpress.com') disp(' ') disp('MFILE SOURCE') disp(' http://numericalmethods.eng.usf.edu/blog/nonlinear_equation_blog.m') disp(' ') disp('LAST REVISED') disp(' January 17, 2012') disp(' ')
ABSTRACT This program shows you an how to solve nonlinear equations AUTHOR Sri Harsha Garapati, Daniel Miller and Autar K Kaw of http://autarkaw.wordpress.com MFILE SOURCE http://numericalmethods.eng.usf.edu/blog/nonlinear_equation_blog.m LAST REVISED January 17, 2012
INPUTS
syms x % nonlinear equation to be solved eqn='3*x^3-15*x^2+47*x=33';
DISPLAYING INPUTS
disp('INPUTS') fprintf(' The equation to solve is: %s\n\n',char(eqn))
INPUTS The equation to solve is: 3*x^3-15*x^2+47*x=33
THE CODE
using the solve command
soln=solve(eqn,x);
% converting the exact answer to decimal format using double
soln=double(soln);
DISPLAYING OUTPUTS
disp(' ') disp('OUTPUTS') disp(' The complete solution to the equation is:') disp(soln)
OUTPUTS The complete solution to the equation is: 0.9244 2.0378 - 2.7833i 2.0378 + 2.7833i